Topics · 3 identities

Double Angle

Rewriting functions of 2θ in terms of functions of θ.

sin 2θ

sin2θ=2sinθcosθ\sin 2\theta = 2 \sin\theta \cos\theta
Open identity

cos 2θ

cos2θ=cos2θsin2θ=2cos2θ1=12sin2θ\cos 2\theta = \cos^{2}\theta - \sin^{2}\theta = 2\cos^{2}\theta - 1 = 1 - 2\sin^{2}\theta
Open identity

tan 2θ

tan2θ=2tanθ1tan2θ\tan 2\theta = \dfrac{2\tan\theta}{1 - \tan^{2}\theta}
Open identity